100. Same Tree — LeetCode Solution

Given two binary trees, write a function to check if they are the same or not.

Two binary trees are considered the same if they are structurally identical and the nodes have the same value.

Example 1:

Input:     1         1
          / \       / \
         2   3     2   3
        [1,2,3],   [1,2,3]
Output: true

Example 2:

Input:     1         1
          /           \
         2             2
        [1,2],     [1,null,2]
Output: false

Example 3:

Input:     1         1
          / \       / \
         2   1     1   2
        [1,2,1],   [1,1,2]
Output: false

Here is my solution:

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public boolean isSameTree(TreeNode p, TreeNode q) { 
        if (p == null && q == null) {
            return true;
        }
        if (p == null || q == null) {
            return false;
        }
        
        return p.val == q.val && isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
    }
}

You can checkout the full explanation by watching the below video: